Most residents in poverty, US cities · 1990
US cities with the most residents living below the poverty line, as of the 1990 American Community Survey. Ranked by number of people, not the poverty rate. New York, New York leads at 1,412,267. 6,058 cities qualify in total. Cities with fewer than 5,000 residents are excluded. California carries 4 of the top 25 entries.
UPDATED 2026-07-15 · DATA: US CENSUS BUREAU DECENNIAL CENSUS
Frequently asked
Which city has the highest residents in poverty?
New York, New York ranks #1 with 1,412,267 (1990 Decennial Census).
What are the top 5 cities by residents in poverty?
New York, New York, Los Angeles, California, Chicago, Illinois, Houston, Texas, Detroit, Michigan.
How many cities are in this ranking?
6,058 cities qualify after filtering for population minimums and data availability (minimum 5,000 residents). The ranking covers 1990 Decennial Census data.
How is residents in poverty measured?
Estimated number of residents living below the federal poverty line, from the poverty rate applied to total population. Source: US Census Bureau, 1990 Decennial Census.