RANKING · 2010 CENSUS · 500 SHOWN OF 918
Most income inequality (Gini), US metro areas · 2010
US metro areas ranked by Gini index of household income inequality, where 0 = perfect equality and 1 = maximum inequality (2010 ACS). Clarksdale, MS leads at 0.548. 918 metro areas qualify in total. Texas carries 7 of the top 25 entries.
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RANKPLACESTATEPOPINCOME INEQUALITY (GINI)VS –
USUnited States308,745,5380.461–
UPDATED 2026-07-15 · DATA: US CENSUS BUREAU DECENNIAL CENSUS
Frequently asked
Which metro area has the highest income inequality (gini)?
Clarksdale, MS ranks #1 with 0.548 (2010 Decennial Census).
What are the top 5 metro areas by income inequality (gini)?
Clarksdale, MS, Nantucket, MA, Raymondville, TX, Andrews, TX, Cleveland, MS.
How many metro areas are in this ranking?
918 metro areas qualify after filtering for population minimums and data availability. The ranking covers 2010 Decennial Census data.
How is income inequality (gini) measured?
Gini index of household income inequality. 0 = perfect equality, 1 = maximum inequality. Source: ACS B19083. Source: US Census Bureau, 2010 Decennial Census.