Most income inequality (Gini), US cities
US cities ranked by Gini index of household income inequality, where 0 = perfect equality and 1 = maximum inequality (2024 ACS). Darlington, South Carolina leads at 0.715. 6,822 cities qualify in total. Cities with fewer than 5,000 residents are excluded. Texas carries 4 of the top 25 entries.
Flip the list · Most equal income distribution, US cities →UPDATED 2026-07-15 · DATA: US CENSUS BUREAU ACS 5-YEAR ESTIMATES
Frequently asked
Which city has the highest income inequality (gini)?
Darlington, South Carolina ranks #1 with 0.715 (2024 American Community Survey).
What are the top 5 cities by income inequality (gini)?
Darlington, South Carolina, Roma, Texas, Milledgeville, Georgia, Naples Manor, Florida, Aspen, Colorado.
How many cities are in this ranking?
6,822 cities qualify after filtering for population minimums and data availability (minimum 5,000 residents). The ranking covers 2024 ACS 5-year data.
How is income inequality (gini) measured?
Gini index of household income inequality. 0 = perfect equality, 1 = maximum inequality. Source: ACS B19083. Source: US Census Bureau, American Community Survey 5-year estimates (2024).