Most income inequality (Gini), US cities · 2010
US cities ranked by Gini index of household income inequality, where 0 = perfect equality and 1 = maximum inequality (2023 ACS). Aspen, Colorado leads at 0.634. 6,639 cities qualify in total. Cities with fewer than 5,000 residents are excluded. California carries 5 of the top 25 entries.
Flip the list · Most equal income distribution, US cities →UPDATED 2026-06-02 · DATA: US CENSUS BUREAU ACS 5-YEAR ESTIMATES
Frequently asked
Which city has the highest income inequality (gini)?
Aspen, Colorado ranks #1 with 0.634 (2010 American Community Survey).
What are the top 5 cities by income inequality (gini)?
Aspen, Colorado, Pikeville, Kentucky, Stanford, California, Palm Beach, Florida, Flowood, Mississippi.
How many cities are in this ranking?
6,639 cities qualify after filtering for population minimums and data availability (minimum 5,000 residents). The ranking covers 2010 ACS 5-year data.
How is income inequality (gini) measured?
Gini index of household income inequality. 0 = perfect equality, 1 = maximum inequality. Source: ACS B19083. Source: US Census Bureau, American Community Survey 5-year estimates (2010).