RANKING · 2010 CENSUS · 500 SHOWN OF 3,131
Most equal income distribution, US counties · 2010
US counties with the lowest income inequality, measured by the Gini index (2010 ACS). Loving County, Texas leads at 0.207. 3,131 counties qualify in total. Nebraska carries 5 of the top 25 entries.
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RANKPLACESTATEPOPINCOME INEQUALITY (GINI)VS –
USUnited States308,745,5380.461–
UPDATED 2026-07-15 · DATA: US CENSUS BUREAU DECENNIAL CENSUS
Frequently asked
Which county has the lowest income inequality (gini)?
Loving County, Texas ranks #1 with 0.207 (2010 Decennial Census).
What are the top 5 counties by income inequality (gini)?
Loving County, Texas, Kalawao County, Hawaii, McPherson County, Nebraska, San Juan County, Colorado, Logan County, Nebraska.
How many counties are in this ranking?
3,131 counties qualify after filtering for population minimums and data availability. The ranking covers 2010 Decennial Census data.
How is income inequality (gini) measured?
Gini index of household income inequality. 0 = perfect equality, 1 = maximum inequality. Source: ACS B19083. Source: US Census Bureau, 2010 Decennial Census.