Most equal income distribution, US cities · 2010
US cities with the lowest income inequality, measured by the Gini index (2023 ACS). Belle Mead, New Jersey leads at 0.161. 6,639 cities qualify in total. Cities with fewer than 5,000 residents are excluded. Texas carries 5 of the top 25 entries.
Flip the list · Most income inequality (Gini), US cities →UPDATED 2026-06-02 · DATA: US CENSUS BUREAU ACS 5-YEAR ESTIMATES
Frequently asked
Which city has the lowest income inequality (gini)?
Belle Mead, New Jersey ranks #1 with 0.161 (2010 American Community Survey).
What are the top 5 cities by income inequality (gini)?
Belle Mead, New Jersey, Country Knolls, New York, Travis Ranch, Texas, Volo, Illinois, Fort Knox, Kentucky.
How many cities are in this ranking?
6,639 cities qualify after filtering for population minimums and data availability (minimum 5,000 residents). The ranking covers 2010 ACS 5-year data.
How is income inequality (gini) measured?
Gini index of household income inequality. 0 = perfect equality, 1 = maximum inequality. Source: ACS B19083. Source: US Census Bureau, American Community Survey 5-year estimates (2010).